Sunday, September 15, 2013

Hydrogen Gas

Purpose: To determine the percent yield of hydrogen liquidate produced in the reaction of magnesium with hydrochloride acidulous Materials: Electronic equipoise scale splatter measuring tube 10mL or 25mL ammonia alum cylinder Retort stand and clamp chiliad mL graduated cylinder containing about 800mL of pee which has been brought to mode temperature bulls eye wire 1 hole 00 rubber stopper 2.5 cm gaffe of Mg ribbon steel wool 6 groin of dm3 HCL(aq) information Table1: Quantitative observations of magnesium reacting with hydrochloride acid Substances criterion including uncertainty Mass of 2.5cm magnesium 0.037g±0.0005 mode temperature19°C±0.5 volume of 6.00 dm3 HCL(aq) used15.1cm3 ±0.5 Volume of bollixoline collected ( urine levels are equal to room pressure)36.5cm3 ±0.1 continuance of magnesium2.6cm±0.05 Table2: Qualitative observations of the magnesium, reacting in the hydrochloride acid SubstancesQualitative Observations 2 .
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5cm Magnesium (Mg) ribbon pass away away thin strip hard Shiny tensile Hydrochloride acid (HCL)Transparent bonny like water The reaction occurred when the hydrochloride acid reaches the magnesium (Mg) ribbon startle to dissolve Separating the H2 go down on from the water gas bubbles attached to copper wire by and by the reaction occurred (the period of 5 minutes waiting for the gas in the test tube to come to room temperature)No much air bubbles No change of colour Transparent water Gas bubbles attached to copper coil Temperature of the water after the reaction19.5°C ±0.5 Pressure101.38kPa Calculations: Step 1: Equation Mg(s) + ! 2HCL (aq) MgCl2 (aq) + H2 (g) Step 2: pose the number of moles of Mg n = m/M Molar mass of Mg = 24.31g/mol m = 0.037±0.0005g n = 0.037±0.0005g ÷ 24.31g/mol n = 1.52x10-3 ±0.0005mol Uncertainty Calculations: 0.0005 ÷ 0.037g x coke = 1.4% 0.0005 ÷24.31g/mol x 100 = 0.002% 1.4% + 0.002% = 1.402% 1.402% of 0.037 = 0.0005 Therefore the uncertainty is ±0.0005 Since the...If you fate to pick up a full essay, order it on our website: BestEssayCheap.com

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